Integrand size = 26, antiderivative size = 98 \[ \int \frac {x^3 (a+b \text {arcsinh}(c x))}{\sqrt {\pi +c^2 \pi x^2}} \, dx=\frac {2 b x}{3 c^3 \sqrt {\pi }}-\frac {b x^3}{9 c \sqrt {\pi }}-\frac {2 \sqrt {\pi +c^2 \pi x^2} (a+b \text {arcsinh}(c x))}{3 c^4 \pi }+\frac {x^2 \sqrt {\pi +c^2 \pi x^2} (a+b \text {arcsinh}(c x))}{3 c^2 \pi } \]
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Time = 0.11 (sec) , antiderivative size = 98, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.154, Rules used = {5812, 5798, 8, 30} \[ \int \frac {x^3 (a+b \text {arcsinh}(c x))}{\sqrt {\pi +c^2 \pi x^2}} \, dx=\frac {x^2 \sqrt {\pi c^2 x^2+\pi } (a+b \text {arcsinh}(c x))}{3 \pi c^2}-\frac {2 \sqrt {\pi c^2 x^2+\pi } (a+b \text {arcsinh}(c x))}{3 \pi c^4}+\frac {2 b x}{3 \sqrt {\pi } c^3}-\frac {b x^3}{9 \sqrt {\pi } c} \]
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Rule 8
Rule 30
Rule 5798
Rule 5812
Rubi steps \begin{align*} \text {integral}& = \frac {x^2 \sqrt {\pi +c^2 \pi x^2} (a+b \text {arcsinh}(c x))}{3 c^2 \pi }-\frac {2 \int \frac {x (a+b \text {arcsinh}(c x))}{\sqrt {\pi +c^2 \pi x^2}} \, dx}{3 c^2}-\frac {b \int x^2 \, dx}{3 c \sqrt {\pi }} \\ & = -\frac {b x^3}{9 c \sqrt {\pi }}-\frac {2 \sqrt {\pi +c^2 \pi x^2} (a+b \text {arcsinh}(c x))}{3 c^4 \pi }+\frac {x^2 \sqrt {\pi +c^2 \pi x^2} (a+b \text {arcsinh}(c x))}{3 c^2 \pi }+\frac {(2 b) \int 1 \, dx}{3 c^3 \sqrt {\pi }} \\ & = \frac {2 b x}{3 c^3 \sqrt {\pi }}-\frac {b x^3}{9 c \sqrt {\pi }}-\frac {2 \sqrt {\pi +c^2 \pi x^2} (a+b \text {arcsinh}(c x))}{3 c^4 \pi }+\frac {x^2 \sqrt {\pi +c^2 \pi x^2} (a+b \text {arcsinh}(c x))}{3 c^2 \pi } \\ \end{align*}
Time = 0.20 (sec) , antiderivative size = 82, normalized size of antiderivative = 0.84 \[ \int \frac {x^3 (a+b \text {arcsinh}(c x))}{\sqrt {\pi +c^2 \pi x^2}} \, dx=\frac {3 a \left (-2+c^2 x^2\right ) \sqrt {1+c^2 x^2}+b \left (6 c x-c^3 x^3\right )+3 b \left (-2+c^2 x^2\right ) \sqrt {1+c^2 x^2} \text {arcsinh}(c x)}{9 c^4 \sqrt {\pi }} \]
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Time = 0.20 (sec) , antiderivative size = 133, normalized size of antiderivative = 1.36
method | result | size |
default | \(a \left (\frac {x^{2} \sqrt {\pi \,c^{2} x^{2}+\pi }}{3 \pi \,c^{2}}-\frac {2 \sqrt {\pi \,c^{2} x^{2}+\pi }}{3 \pi \,c^{4}}\right )+\frac {b \left (3 \,\operatorname {arcsinh}\left (c x \right ) c^{4} x^{4}-3 \,\operatorname {arcsinh}\left (c x \right ) c^{2} x^{2}-c^{3} x^{3} \sqrt {c^{2} x^{2}+1}-6 \,\operatorname {arcsinh}\left (c x \right )+6 c x \sqrt {c^{2} x^{2}+1}\right )}{9 c^{4} \sqrt {\pi }\, \sqrt {c^{2} x^{2}+1}}\) | \(133\) |
parts | \(a \left (\frac {x^{2} \sqrt {\pi \,c^{2} x^{2}+\pi }}{3 \pi \,c^{2}}-\frac {2 \sqrt {\pi \,c^{2} x^{2}+\pi }}{3 \pi \,c^{4}}\right )+\frac {b \left (3 \,\operatorname {arcsinh}\left (c x \right ) c^{4} x^{4}-3 \,\operatorname {arcsinh}\left (c x \right ) c^{2} x^{2}-c^{3} x^{3} \sqrt {c^{2} x^{2}+1}-6 \,\operatorname {arcsinh}\left (c x \right )+6 c x \sqrt {c^{2} x^{2}+1}\right )}{9 c^{4} \sqrt {\pi }\, \sqrt {c^{2} x^{2}+1}}\) | \(133\) |
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Time = 0.30 (sec) , antiderivative size = 132, normalized size of antiderivative = 1.35 \[ \int \frac {x^3 (a+b \text {arcsinh}(c x))}{\sqrt {\pi +c^2 \pi x^2}} \, dx=\frac {3 \, \sqrt {\pi + \pi c^{2} x^{2}} {\left (b c^{4} x^{4} - b c^{2} x^{2} - 2 \, b\right )} \log \left (c x + \sqrt {c^{2} x^{2} + 1}\right ) + \sqrt {\pi + \pi c^{2} x^{2}} {\left (3 \, a c^{4} x^{4} - 3 \, a c^{2} x^{2} - {\left (b c^{3} x^{3} - 6 \, b c x\right )} \sqrt {c^{2} x^{2} + 1} - 6 \, a\right )}}{9 \, {\left (\pi c^{6} x^{2} + \pi c^{4}\right )}} \]
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Time = 1.32 (sec) , antiderivative size = 124, normalized size of antiderivative = 1.27 \[ \int \frac {x^3 (a+b \text {arcsinh}(c x))}{\sqrt {\pi +c^2 \pi x^2}} \, dx=\frac {a \left (\begin {cases} \frac {x^{2} \sqrt {c^{2} x^{2} + 1}}{3 c^{2}} - \frac {2 \sqrt {c^{2} x^{2} + 1}}{3 c^{4}} & \text {for}\: c^{2} \neq 0 \\\frac {x^{4}}{4} & \text {otherwise} \end {cases}\right )}{\sqrt {\pi }} + \frac {b \left (\begin {cases} - \frac {x^{3}}{9 c} + \frac {x^{2} \sqrt {c^{2} x^{2} + 1} \operatorname {asinh}{\left (c x \right )}}{3 c^{2}} + \frac {2 x}{3 c^{3}} - \frac {2 \sqrt {c^{2} x^{2} + 1} \operatorname {asinh}{\left (c x \right )}}{3 c^{4}} & \text {for}\: c \neq 0 \\0 & \text {otherwise} \end {cases}\right )}{\sqrt {\pi }} \]
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Time = 0.20 (sec) , antiderivative size = 117, normalized size of antiderivative = 1.19 \[ \int \frac {x^3 (a+b \text {arcsinh}(c x))}{\sqrt {\pi +c^2 \pi x^2}} \, dx=\frac {1}{3} \, b {\left (\frac {\sqrt {\pi + \pi c^{2} x^{2}} x^{2}}{\pi c^{2}} - \frac {2 \, \sqrt {\pi + \pi c^{2} x^{2}}}{\pi c^{4}}\right )} \operatorname {arsinh}\left (c x\right ) + \frac {1}{3} \, a {\left (\frac {\sqrt {\pi + \pi c^{2} x^{2}} x^{2}}{\pi c^{2}} - \frac {2 \, \sqrt {\pi + \pi c^{2} x^{2}}}{\pi c^{4}}\right )} - \frac {{\left (c^{2} x^{3} - 6 \, x\right )} b}{9 \, \sqrt {\pi } c^{3}} \]
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Exception generated. \[ \int \frac {x^3 (a+b \text {arcsinh}(c x))}{\sqrt {\pi +c^2 \pi x^2}} \, dx=\text {Exception raised: TypeError} \]
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Timed out. \[ \int \frac {x^3 (a+b \text {arcsinh}(c x))}{\sqrt {\pi +c^2 \pi x^2}} \, dx=\int \frac {x^3\,\left (a+b\,\mathrm {asinh}\left (c\,x\right )\right )}{\sqrt {\Pi \,c^2\,x^2+\Pi }} \,d x \]
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